3^x^+^3-3^x^+^2=486

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Solution for 3^x^+^3-3^x^+^2=486 equation: 



3^x^+^3-3^x^+^2=486

We move all terms to the left:

3^x^+^3-3^x^+^2-(486)=0

determiningTheFunctionDomain
3^x^-3^x^-486+^3+^2=0

We add all the numbers together, and all the variables

3^x^-3^x^=0

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